Pragyan 2020 - ASCII Sentence
Posted on mer. 26 février 2020 in CTF • Tagged with hack, learn, ctf, pragyan, cryptography, 2020, flagoverbeer, ascii, python
solves : 123
Decode this
8951116499911082102898878115975057102908657109985070102908786108885053110907210811910072108102908710451975182112885057105102816161
Since it's ASCII, we need to create correct value in order to process it.
import base64
decode = "8951116499911082102898878115975057102908657109985070102908786108885053110907210811910072108102908710451975182112885057105102816161"
asci = []
x = 0
while x < len(decode):
if int(decode[x]) == 1:
asci.append(chr(int(decode[x] + decode[x+1] + decode[x+2])))
i = 3
else …Continue reading